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Old Jun 30, 2002 | 9:00 pm
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Pickles
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<font face="Verdana, Arial, Helvetica, sans-serif" size="2">Originally posted by VolleyballFerd:
Don't be too surprised - the actually figures for the 4 categories are:

2 in 9, 2 in 9, 4 in 9 and 1 in 9 - exactly.

In order to get those numbers exactly, you would almost certainly have only a total of 9 respondents. Possibly it could occur with 18 - but even that is a pretty small sample size.
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Actually, these percentages would occur with ANY multiple of these fractions. And if your sample was 81, what is wrong with 18/81,18/81,36/81, and 9/81? Any more (or less) likely than 20/90,20/90,40/90 and 10/90? The basic laws of sampling, arithmetic distribution and association apply even in FlyerTalk.
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