<font face="Verdana, Arial, Helvetica, sans-serif" size="2">Originally posted by wormwood:
As always, I wonder about the multiplier effect of something like this (see also mile inflation threads). BA isn't going to be in the business of Concording people who buy subscriptions, that isn't viable for them.</font>
Sure it is. Providing transport on the Concorde for someone that buys InsideFlyer subscriptions is no different than doing so for someone that has the BA Visa, charges a lot, but has never flown on a BA revenune ticket. BA gets money from the bank or Starwood either way. For someone redeeming through Qantas, presumably BA is getting some money from Qantas (or at least an offset for transactions in the opposite direction), Qantas got money from Starwood, Starwood got money from InsideFlyer, and InsideFlyer got money from the passenger. In fact, BA is probably the only party really making money off this transaction, aside from InsideFlyer should people renew. The more the merrier, I'd say would be BA's attitude.
The only case where BA would be concerned is if there were passengers that otherwise would have actually purchased a $12,000 Concorde ticket and are instead "buying" one through this round-about offer.
How many FlyerTalkers are actually going to take advantage of this offer and use it for the Starwood-QF-BA Concorde deal? Maybe a dozen or two? I don't think this is going to be of much concern. The big danger would be if a ticket broker got wind of this, bought a huge amount of miles, then sold "discount" Concorde tickets to the general public.
I suspect that far more people bought subscriptions for Starwood points to use for hotel stays, or to top off airline accounts that they otherwise use on a regular basis. That's what I did. I think I'm otherwise a good customer of Starwood, in that I stay with them when possible and use my Starwood Amex a lot, and I'm a good customer of the airlines that I plan to transfer points to, so I think that they'd all be happy that I'm participating in their programs more.